How do you balance $Fe(s) + S(s) -> Fe_2S_3(s)$ ?

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Answer 1 · 2017-02-22T17:45:03

$2Fe_(s)$ + $3S_(s)$ ------------> $Fe_2S_3$

Step 1 : First of all write the equation
$Fe_(s)$ + $S_(s)$ ------------> $Fe_2S_3$

Step 2 : Now balance the number of $Fe$ atoms on both reactant and product side

Here reactant side has one $Fe_(S)$ atom and product side has $2$ atoms of $Fe_(S)$ , therefore multiply $Fe_(S)$ at reactant side by $2$

Step 3: Balance $S_(s)$

Here reactant side has one $S_(s)$ atom and product side has $3$ atoms of $S_(s)$ , therefore multiply $S_(s)$ at reactant side by $3$

Step 4.
Write the final eqaution

$2Fe_(s)$ + $3S_(s)$ ------------> $Fe_2S_3$

How do you balance Fe(s) + S(s) -> Fe_2S_3(s)Fe(s) + S(s) -> Fe_2S_3(s)?