How do you write the equation of a line given (-3,2) (3,6)?

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Answer 1 · 2017-02-22T15:33:10

#y = 2/3x + 4#

#(-3,2) and (3,6)#
#y = mx + b#

For #m#, which is slope

#(y_2-y_1)/(x_2-x_1) = m " (slope)"#

so

#(6-2)/(3 - (-3)) = 4/6 = 2/3 = m#

#y = 2/3x + b#

for b - use one of the points for #(x,y)#

#y=2/3x + b#
#6= 2/3(3) + b#
#6= 2 + b#

#4=b#

Now we have #m and b#