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How do you integrate #int (root3x)#?

1 Answer

Feb 21, 2017

#int root(3)x dx = 3/4 xroot(3)x +C#

Explanation:

You can integrate using the power rule:

#int x^alpha dx = x^(alpha+1)/(alpha+1) + C#

In our case:

#int root(3)x dx = int x^(1/3)dx = x^(4/3)/(4/3) + C = 3/4 xroot(3)x +C#

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