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Answer 1 · 2017-02-13T03:10:33

#1040g#

The balanced equation for the combustion of octane is:
#2C_8H_18 + 25O_2 -> 16CO_2 + 18H_2O#

Therefore,
a. Calculate the number of moles of octane:
#235g * "1mol"/"114.26g" = 2.96mol#

b. Calculate the grams of carbon dioxide:
#2.96 "mol octane" * (16 "mol CO2")/(2 "mol octane") * (44.01g CO2)/(1 mol CO2) = 1042g #

(To the appropriate number of sig figs: 1040g).