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How do you integrate #int root3(x^2)dx#?

1 Answer

Jan 27, 2017

By the Power Law: #3/4x^(4/3)#

Explanation:

#root3(x^2)=x^(1/3)#. Hence using the Power Law (#int x^n dx=1/(n+1)x^(n+1)+c, n!=0#) you get #1/(1/3+1)x^(1/3+1)+c#

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