How do you solve the quadratic using the quadratic formula given $3 a^{2} = 6 a - 3$ $3a^2=6a-3$ ?

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How do you solve the quadratic using the quadratic formula given $3 a^{2} = 6 a - 3$ $3a^2=6a-3$ ?

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Answer 1 · 2017-01-17T23:43:02

$a = 1$ $a=1$

Explanation:

Rearrange:
$3 a^{2} - 6 a + 3 = 0$ $3a^2-6a+3=0$

Use the formula $a = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $a=(-b+-sqrt(b^2-4ac))/(2a)$ taking care not to get the $a$ $a$ 's muddled

Formula Problem
a 3
b -6
c 3
x a

$a = \frac{- (- 6) \pm \sqrt{{(- 6)}^{2} - 4 \times 3 \times 3}}{2 \times 3}$ $a=(-(-6)+-sqrt((-6)^2-4 xx 3 xx 3))/(2 xx 3)$
$a = \frac{6 \pm 0}{2 \times 3}$ $a=(6+-0)/(2 xx 3)$
$a = 1$ $a=1$ (repeated root).

Check: $3 \times {(1)}^{2} = 3$ $3xx(1)^2=3$ and $6 \times (1) - 3 = 3$ $6xx(1)-3=3$

If you get muddled over the $a$ $a$ 's just replace all the $a$ $a$ 's with $x$ $x$ 's, apply the formula, then at the step replace the $x$ $x$ with $a$ $a$ .

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How do you solve the quadratic using the quadratic formula given $3 a^{2} = 6 a - 3$ $3a^2=6a-3$ ?

1 Answer

Explanation:

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How do you solve the quadratic using the quadratic formula given $3 a^{2} = 6 a - 3$ $3a^2=6a-3$ ?