How do you solve the quadratic using the quadratic formula given $3a^2=6a-3$ ?

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Answer 1 · 2017-01-17T23:43:02

$a=1$

Rearrange:
$3a^2-6a+3=0$

Use the formula $a=(-b+-sqrt(b^2-4ac))/(2a)$ taking care not to get the $a$ 's muddled

Formula Problem
a 3
b -6
c 3
x a

$a=(-(-6)+-sqrt((-6)^2-4 xx 3 xx 3))/(2 xx 3)$
$a=(6+-0)/(2 xx 3)$
$a=1$ (repeated root).

Check: $3xx(1)^2=3$ and $6xx(1)-3=3$

If you get muddled over the $a$ 's just replace all the $a$ 's with $x$ 's, apply the formula, then at the step replace the $x$ with $a$ .

How do you solve the quadratic using the quadratic formula given 3a^2=6a-33a^2=6a-3?