How do you evaluate $c - (a + 3) + 4 + b$ $c- ( a + 3) + 4+ b$ for $a = 1, b = 1$ $a=1, b=1$ and $c = 4$ $c=4$ ?

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Answer 1 · 2017-01-06T17:58:20

Plug the variables into the expression

$5$ $5$

Because $a = 1, b = 1, and c = 4$ $a=1, b=1, and c=4$ , you would plug those numbers into the expression.

$c - (a + 3) + 4 + b becomes 4 - (1 + 3) + 4 + 1$ $c-(a+3)+4+b " becomes " 4-(1+3)+4+1$

Then the problem is a case of simplifying.

Calculate inside the parenthesis first $(1 + 3)$ $(1+3)$ to get $4$ $4$

Your expression then becomes:

$4 - (4) + 4 + 1$ $4-(4) +4+1$ . You would then simplify further:

$= 4 - 4 + 4 + 1$ $= 4-4+4+1$

$= 5$ $=5$ .

How do you evaluate c- ( a + 3) + 4+ bc−(a+3)+4+bc- ( a + 3) + 4+ b for a=1, b=1a=1,b=1a=1, b=1 and c=4c=4c=4?