How do you divide #x^2-4x-3# by #x+5#?

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How do you divide #x^2-4x-3# by #x+5#?

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Answer 1 · 2016-12-23T22:06:40

#x+1 +2/(x+5)#

Explanation:

Divide #x^2-4x-3# by #x+5#.

#color(white)(aaaaaaaaaa^1a)x+1 +2/(x+5)#
#color(white)(aaaaa)----------#
#x-5 | color(white)ax^2-4x-3#
#color(white)(aa^2a)-(x^2-5x)color(white)(a)darr#
#color(white)(aaaaaa)----#
#color(white)(aaaaaaaaaaaa)x-3#
#color(white)(aaaaaaaaa)-(x-5)#
#color(white)(aaaaaaaaa)----#
#color(white)(aaaaaaaa^2aaaaaaa)2#

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How do you divide #x^2-4x-3# by #x+5#?

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