How do you solve $x^2=-8x-16$ ?

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Answer 1 · 2016-12-12T23:58:12

$x = -4$

You would move $x^2$ to the opposite side of the equal sign, changing its sign.

The new equation would be

$-x^2 -8 x - 16 = 0$

To solve the equation, you could use the quadratic formula or factor it. In this case, factoring the equation would be the easiest way to go.

$-(x^2 + 8x + 16)=0$

$-(x + 4)^2=0$

Therefore,

$x = -4$

How do you solve x^2=-8x-16x^2=-8x-16?