How do you solve #x^2=-8x-16#?

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Answer 1 · 2016-12-12T23:58:12

#x = -4#

You would move #x^2# to the opposite side of the equal sign, changing its sign.

The new equation would be

#-x^2 -8 x - 16 = 0#

To solve the equation, you could use the quadratic formula or factor it. In this case, factoring the equation would be the easiest way to go.

#-(x^2 + 8x + 16)=0#

#-(x + 4)^2=0#

Therefore,

#x = -4#