How do you solve $x^{2} = - 8 x - 16$ $x^2=-8x-16$ ?

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Answer 1 · 2016-12-12T23:58:12

$x = - 4$ $x = -4$

You would move $x^{2}$ $x^2$ to the opposite side of the equal sign, changing its sign.

The new equation would be

$- x^{2} - 8 x - 16 = 0$ $-x^2 -8 x - 16 = 0$

To solve the equation, you could use the quadratic formula or factor it. In this case, factoring the equation would be the easiest way to go.

$- (x^{2} + 8 x + 16) = 0$ $-(x^2 + 8x + 16)=0$

$- {(x + 4)}^{2} = 0$ $-(x + 4)^2=0$

Therefore,

$x = - 4$ $x = -4$

How do you solve x2=−8x−16x^2=-8x-16?