For an X-linked recessive trait, 9% of the females in the population are affected. What percent of the males would be affected? What percentage of the population is represented by the carriers?

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Answer 1 · 2016-12-12T00:55:27

Castle Hardy Weinburg for the female population only:

$1 = q^{2} + 2 \cdot p \cdot q + p^{2}$ $1 = q^2 + 2*p*q + p^2$

$1 = q + p$ $1 = q + p$

where it tells you that $p^{2} = 0.09$ $p^2 = 0.09$ , so

$p = 0.3$ $p = 0.3" "$ and $q = 0.7$ $" "q = 0.7$ .

Carriers are heterozygous females, so:

$heterozygous = 2 \cdot p \cdot q = 2 \cdot 0.3 \cdot 0.7 = 0.42$ $"heterozygous" = 2 * p * q = 2 * 0.3 * 0.7 = 0.42$

$42 %$ $42%$ of females are carriers.

That's the first part.