A function is given as $f(x)=2x^2 -12x+ 3$ . How do you write the vertex form of the given equation?

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Answer 1 · 2016-12-08T02:55:28

$2(x-3)^2 - 15$

vertex form is $a(x - h)^2 + k$

$2x^2 -12x +3$

$2(x^2-6x) +3$

$2(x^2-6x+9-9) +3$

$2(x^2-6x+9) +3 -18$

$2(x-3)^2 -15$

which tells us that it is a positive graph with vertex ( 3, -15 )

A function is given as f(x)=2x^2 -12x+ 3f(x)=2x^2 -12x+ 3. How do you write the vertex form of the given equation?