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If #F(x) = x^(2/3)# What is #f'(x)# ?

1 Answer

Dec 7, 2016

#f'(x) = 2/(3root3x)#

Explanation:

NB: I have assumed that the upper case #F(x)# in the question is a meant to be the same as #f(x)#
#f(x) = x^(2/3)#

Using the power rule:

#f'(x) = 2/3 x^(2/3-1)#

#= 2/3x^(-1/3)#

#= 2/(3root3x)#

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