Question #41c0d

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Answer 1 · 2016-11-28T18:48:00

$tanx=3/4$

Draw the angle in the first quadrant. The hypotenuse will be $5$ and the adjacent will be $4$ , since

$cosx = "adjacent"/"hypotenuse"$

Then use the Pythagorean Theorem to solve for the remaining side, which comes out to 3.

$a^2 + b^2 = c^2$

$4^2 + b^2 = 5^2$

$16 + b^2 = 25$

$b^2 = 25 - 16$

$b^2 = 9$

$b = sqrt 9$

$b = 3$

So the side opposite to the angle $x$ in the triangle is $3$ . Then, since

$tan(x) = "opposite"/ "adjacent"$

you have

$tanx= 3/4$