How do you solve the system of equations #-4x + 6y = 4# and #- x + 8y = 1#?
1 Answer
Explanation:
#{(-4x + 6y = 4), (-x + 8y = 1) :}#
#{(-4x + 6y = 4), ( (-x + 8y = 1) * (-4)) :}#
#{(-4x + 6y = 4), (4x - 32y = -4) :}#
Add these together to get
#-26y = 0#
Therefore
#y=0#
Plug
#-x + (8 * 0) = 1#
#-x = 1#
#x = -1#
Check your answer by putting
#(-4 x -1) + (6 * 0) = 4#
#4 + 0 = 4#
#4 = 4#
:)