How do you multiply and simplify #\frac { 79n } { 25} \cdot \frac { 85} { 27n ^ { 2} }#?

2 Answers
smendyka
Nov 20, 2016

#1343/(135n)#

Explanation:

To multiply fractions you multiply then numerator by the numerator and the denominator by the denominator and then factor. Or factor first and then multiply.

#(79n*85)/(25*27n^2) =>#

#(6715n)/(675n^2) =>#

#1343/(135n) (5n)/(5n) =>#

#1343/(135n) * 1 =>#

#1343/(135n)#

EZ as pi
Nov 20, 2016

#=1343/(135n)#

Explanation:

When multiplying with fractions you can simplify (cancel) any numerator with any denominator as long as there is a multiplication between them.
Cancelling first means the numbers stay small enough to work with without having to simplify unwieldy fractions.

#(79n)/25 xx 85/(27n^2)" "larr# 25 and 85 have a factor of 5.

#=(79n)/cancel25^5 xx cancel85^17/(27n^2)#

79 and 17 are both prime numbers, so no further cancelling is possible.

#=(1343n)/(135n^2)" "larr#subtract the indices of the variables

#=1343/(135n)#

Related questions
Impact of this question
1555 views around the world
You can reuse this answer
Creative Commons License