How do you differentiate #f(x)=(ax+b)/(cx+d)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Hubert Nov 19, 2016 #f'(x)=(ad-bc)/(cx+d)^2# Explanation: The Quotient Rule: #(f/g)^' =(f' cdot g-f cdot g')/(g^2),\ g !=0# #f(x)=(ax+b)/(cx+d)# #f'(x)=((ax+b)'(cx+d)-(ax+b)(cx+d)')/(cx+d)^2=(a(cx+d)-(ax+b)c)/(cx+d)^2=(ad-bc)/(cx+d)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 29339 views around the world You can reuse this answer Creative Commons License