How do you evaluate the expression when y=3 and x=27 for $x - 6 y$ $x-6y$ ?

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Answer 1 · 2016-11-17T07:41:16

$9$ $9$

To evaluate, substitute the $x$ $x$ and $y$ $y$ in the question with the numbers.

In the expression, $x$ $x$ is equivalent to 27,

and $6 y$ $6y$ is equivalent to $6 \times y$ $6xxy$ , which is $6 \times 3 = 18$ $6xx3=18$

So, $x - 6 y$ $x-6y$

$= 27 - 6 \times 3$ $=27-6xx3$

$= 27 - 18$ $=27-18$

$= 9$ $=9$

How do you evaluate the expression when y=3 and x=27 for x−6yx-6y?