How do you evaluate the expression when y=3 and x=27 for #x-6y#?

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Answer 1 · 2016-11-17T07:41:16

#9#

To evaluate, substitute the #x# and #y# in the question with the numbers.

In the expression, #x# is equivalent to 27,

and #6y# is equivalent to #6xxy#, which is #6xx3=18#

So, #x-6y#

#=27-6xx3#

#=27-18#

#=9#