How do you simplify #(n+4)(n+5)(n+3)!#?

1 Answer
Steve M
Nov 15, 2016

# :. (n+4)(n+5)(n+3)! = (n+5)! #

Explanation:

# (n+4)(n+5)(n+3)! = (n+4)(n+5)(n+3)(n+2)(n+1)(n)(n-1)...1 #

# :. (n+4)(n+5)(n+3)! = (n+5)(n+4)(n+3)(n+2)(n+1)(n)(n-1)...1 #

# :. (n+4)(n+5)(n+3)! = (n+5)! #

Related questions
See all questions in Factorial Identities
Impact of this question
9324 views around the world
You can reuse this answer
Creative Commons License