What are the coordinates of the point of inflection on the graph of #y=x^3-15x^2+33x+100#?

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Answer 1 · 2016-11-11T06:53:37

(5,15)

To find the inflection point, you will need to take the second derivative.

#y=x^3-15x^2+33x+100#

#y'=3x^2-30x+33#

#y''=6x-30#

#6x=30#

#x=5#

Now that you have your #x#, plug it into your first equation:

#y(5)=(5)^3-15(5)^2+33(5)+100#
#=125-375+165+100=15#
The inflection point is (5,15)