How do you use Riemann sums to evaluate the area under the curve of #y = x^2 + 1# on the closed interval [0,1], with n=4 rectangles using midpoint? Calculus Methods of Approximating Integrals RAM (Rectangle Approximation Method/Riemann Sum) 1 Answer Alberto P. Nov 3, 2016 #43/32# Explanation: #sum_(n=1)^4f((2n-1)/8)(1/4)=1/4(1/64+1+9/64+1+25/64+1+49/64+1)=1/4(4+84/64)=1+22/64=1+11/32=43/32# Answer link Related questions What is Integration using rectangles? Find the riemann sum for #f(x)=x+x^2#? How do you Find the Riemann sum for #f(x)=x^3# on the interval #[0,5]# using right endpoints with #n=8#? How do you find Find the Riemann sum that approximates the integral #int_0^9sqrt(1+x^2)dx# using... How do you Use a Riemann sum to approximate the area under the graph of the function #y=f(x)# on... How do you use a Riemann sum to calculate a definite integral? How do you Use a Riemann sum to find area? How do you Use a Riemann sum to find volume? What is a left Riemann sum? What is lower Riemann sum? See all questions in RAM (Rectangle Approximation Method/Riemann Sum) Impact of this question 1582 views around the world You can reuse this answer Creative Commons License