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How do you Find the Riemann sum for #f(x)=x^3# on the interval #[0,5]# using right endpoints with #n=8#?

1 Answer

Nov 12, 2014

Let us find #Delta x#.

#Delta x={b-a}/n={5-0}/8=5/8#

Now, we can find the right sum #R_8#.

#R_8=[f(5/8)+f(10/8)+f(15/8)+f(20/8)+f(25/8)+f(30/8)+f(35/8)+f(40/8)]cdot Delta x#

#=[(5/8)^3+(10/8)^3+(15/8)^3+(20/8)^3+(25/8)^3+(30/8)^3+(35/8)^3+(40/8)^3]cdot 5/8#

#approx 197.75#

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