Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the derivative of #y= 2secx + tanx#?

1 Answer

Nov 3, 2016

#(dy)/(dx)=secx(2tanx+secx)#

Explanation:

Since there is only a simple addition operation, #2secx# and #tanx# can be derived independently.

#d/(dx)2secx=2secxtanx->#since #d/(dx)secx=secxtanx#

#d/(dx)tanx=sec^2x#

#:.(dy)/(dx)=2secxtanx+sec^2x=secx(2tanx+secx)#

Related questions

See all questions in Derivative Rules for y=cos(x) and y=tan(x)

Impact of this question

7817 views around the world

You can reuse this answer
Creative Commons License