How do you find the period of y = 4sin (1/2)(x + pi/4)?

1 Answer
J'Neal
Nov 2, 2016

By getting your equation in the form Asin(Bx+C) and solving (2pi)/|B|

Explanation:

First of all, you want to get your equation in the form of (Bx+C). it's not necessary in this case, but just for the sake of learning and avoiding mistakes, I'm including it anyway. You'll want to multiply (1/2) and (x+pi/4) to get the equation in the form Asin(Bx+C) as 4sin(1/2 x+ pi/8). Now, we are certain that B equals 1/2. Next, we'll plug in to to (2pi)/|B| -> (2pi)/(1/2) = 4pi
The period equals 4pi

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