How do you simplify $5 \sqrt{12} - 2 \sqrt{48} - 7 \sqrt{75}$ $5sqrt12-2sqrt48-7sqrt75$ ?

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How do you simplify $5 \sqrt{12} - 2 \sqrt{48} - 7 \sqrt{75}$ $5sqrt12-2sqrt48-7sqrt75$ ?

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Answer 1 · 2016-10-30T18:47:17

$- 33 \sqrt{3}$ $-33sqrt(3)$

Explanation:

$5 \sqrt{12} = 5 \sqrt{4 \times 3} = 5 \times 2 \sqrt{3} = 10 \sqrt{3}$ $5sqrt(12) =5sqrt(4 xx 3)=5 xx 2sqrt(3)=10sqrt(3)$

$2 \sqrt{48} = 2 \sqrt{16 \times 3} = 2 \times 4 \sqrt{3} = 8 \sqrt{3}$ $2sqrt(48) =2sqrt(16 xx 3)=2 xx 4sqrt(3)=8sqrt(3)$

$7 \sqrt{75} = 7 \sqrt{25 \times 3} = 7 \times 5 \sqrt{3} = 35 \sqrt{3}$ $7sqrt(75) =7sqrt(25 xx 3)=7 xx 5sqrt(3)=35sqrt(3)$

Therefore

$10 \sqrt{3} - 8 \sqrt{3} - 35 \sqrt{3} = - 33 \sqrt{3}$ $10sqrt(3)-8sqrt(3)-35sqrt(3)=-33sqrt(3)$

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How do you simplify $5 \sqrt{12} - 2 \sqrt{48} - 7 \sqrt{75}$ $5sqrt12-2sqrt48-7sqrt75$ ?

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How do you simplify $5 \sqrt{12} - 2 \sqrt{48} - 7 \sqrt{75}$ $5sqrt12-2sqrt48-7sqrt75$ ?