How do you find the derivative of #f(x)=1/x^5#?

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Answer 1 · 2016-10-22T21:57:45

#f'(x)=-5/x^6#

#1/x^5# is the same as #x^-5#

#:.f(x)=x^-5#

#f'(x)=-5x^-6=-5/x^6#

Let #u=1, v=x^5#

#f'(x)=((0)x^5-(1)5x^4)/x^10#

#=(-5x^4)/x^10=-5/x^6#