How do you factor $x^{2} + 3 x - 54$ $x^ { 2} + 3x - 54$ ?

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Answer 1 · 2016-10-20T14:21:21

$(x - 6) (x + 9)$ $(x-6)(x+9)$ are the factors of the quadratic.

$x^{2} + 3 x - 54$ $x^2 +3x - 54$ is called a quadratic trinomial.

Find factors of 54 which differ by +3

= $x^{2} - 6 x + 9 x - 54$ $x^2 - 6x + 9x - 54$

= $x (x - 6) + 9 (x - 6)$ $x(x - 6) +9(x -6)$

= $(x - 6) (x + 9)$ $(x-6)(x+9)$

These are the factors of the expression.

How do you factor x2+3x−54x^ { 2} + 3x - 54?