How do you solve $\frac{6 x - 8}{7} = - 1$ $\frac { 6x - 8} { 7} = - 1$ ?

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Answer 1 · 2016-10-18T20:57:52

the answer is $x = \frac{1}{6}$ $x = 1/6$

First you multiply both sides of the equation by 7 to clear the fraction so

$\frac{7 \times (6 x - 8)}{7} = (7) (- 1)$ $(7xx(6x-8))/7 = (7)(-1)$
which gives

$6 x - 8 = - 7$ $6x-8 = -7$

then you add $8$ $8$ to both sides to begin isolating the x-value

$6 x = - 7 + 8$ $6x = -7+8$ which gives

$6 x = 1$ $6x = 1$

then divide by $6$ $6$ to totally isolate the x

$\frac{6 x}{6} = \frac{1}{6}$ $(6x)/6 = 1/6$

or

$x = \frac{1}{6}$ $x = 1/6$

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