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How do you evaluate #log_15 (1/225)#?

1 Answer

Annie · AJ Speller

Oct 4, 2016

#log_15 (1/225)=-2#

Explanation:

#log_2 8=3# is another way of writing #2^3=8#
That is the easy one to remember!!
So #log_15 (1/225)=x# is the same thing as #15^x=(1/225)#

#15^x=(1/15^2)#
#15^x=15^-2#
So #x=-2#

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