What is the equation of the line normal to $f(x)=(x^2-x)(x-2)$ at $x=1$ ?

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Answer 1 · 2016-09-11T09:29:47

$y=x-1$

Equation of the line normal is $-y'_0(y-y_0)=x-x_0$

$y'=(2x-1)(x-2)+x^2-x=3x^2-6x+2$

$y'_0=-1; y_0=0; x_0=1$

$-(-1)*(y-0)=x-1$

What is the equation of the line normal to f(x)=(x^2-x)(x-2) f(x)=(x^2-x)(x-2) at x=1 x=1?