What is the molarity for 23.4 g of sodium hydroxide in 250.0 mL?

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Answer 1 · 2016-08-17T18:28:33

#"2.34 M"#

The molecular weight of sodium hydroxide is #"39.997 g/mol"#. That is, 1 mole weights #"39.997 g"#.

You have #"23.4 g"#, so you have

#(23.4cancel("g"))/(39.997cancel("g")/"mol") = "0.585 moles"#.

These #0.585# moles are present in #"250 ml"#, and #"250 ml"# is equivalent to #0.25# liters.

Molarity is moles per liter.

#"molarity" = "moles" / "litre"#

#"molarity" = "0.585 moles" / "0.25 L"#

#"molarity " = " 2.34 M"#

Here is a blog post on moles and molarity you might like to look at.