How do you solve #-4y+16=4#?
2 Answers
Aug 16, 2016
y = 3
Explanation:
-4y = 4 - 16 (subtract 16 from both sides)
-4y = -12 (simplify RHS)
y = 3 (divide both sides by -4)
Aug 16, 2016
Explanation:
To solve this equation, isolate the - 4y term on the left of the equation while having numeric values on the right.
To do this, subtract 16 from both sides.
#rArr-4ycancel(+16)cancel(-16)=4-16# we are left with
#-4y=-12# now divide both sides by - 4.
#(cancel(-4)^1 y)/cancel(-4)^1=(-12)/(-4)rArry=3" is the solution"#
