Question #516aa

Question

2060 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-11T18:47:16

#C_M=0.301(mol)/L#

The molarity (#C_M#) is calculated by:

#C_M=n/V#

where, #n# is the number of mole of the solute (#NaOH#) and
#V# is the volume of the solution.

To find the number of mole of #NaOH# we can use the following relationship:

#n=m/(MM)#

where, #m# is the mass of #NaOH# and #MM# is the molar mass of #NaOH#: #MM=40.0g/(mol)#

#=>n=m/(MM)=(29.5cancel(g))/(40.0cancel(g)/(mol))=0.738mol#

The molarity is then can be found as:

#C_M=n/V= (0.738mol)/(2.45L)=0.301(mol)/L ("corrected to 3 significant figures")#