How do you solve #3 cot 2x - sqrt 3 = 0#?

1 Answer

Jul 24, 2016

#pi/6 + (kpi)/2#

Explanation:

#3cot 2x - sqrt3 = 0#
#cot 2x = sqrt3/3#
Trig table --> #cot (pi/3) = sqrt3/3#, then
#2x = pi/3 + kpi#
#x = pi/6# + (kpi)/2
General answer: #x = pi/6 + (kpi)/2#

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How do you solve #3 cot 2x - sqrt 3 = 0#?

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