How do you solve for y in #x=(y+2)/(5y-1)#?

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Answer 1 · 2016-06-19T09:10:11

#color(blue)(y = (2 + x) / (5x - 1)#

#x = (color(blue)(y)+2) / (5color(blue)(y) -1)#

Our main motive in solving this question should be to isolate #color(blue)(y:#

#x * (5color(blue)(y) -1) = color(blue)(y)+2 #

We multiply #x# with both terms within the bracket.

#x * (5color(blue)(y)) + x *( -1) = color(blue)(y)+2 #

#5xcolor(blue)(y) -x = color(blue)(y)+2 #

#5xcolor(blue)(y) - color(blue)(y) = 2 + x#

#color(blue)(y)(5x - 1) = 2 + x#

#color(blue)(y = (2 + x) / (5x - 1)#