What is #3a - (m-4n^2)# when #a = -1, m = -3#, and #n = 2#?

1 Answer
EZ as pi
Jun 13, 2016

#16#

Explanation:

This involves substitution, but as soon as there are negative signs involved, work very carefully.

#a = -1, m = -3, n = 2#
#3a -(m - 4n^2) = 3(-1) - [(-3)-(4(2)^2)]#

#= -3 - [-3 - 4xx4)]#

#= -3 - [-19] = -3 +19#

#=16#

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