How do you simplify #sqrt80 / sqrt5#?

1 Answer
EZ as pi
Jun 8, 2016

#sqrt16 = 4#

Explanation:

Neither 80 nor 5 are square numbers. There are two options:

First method: When we are dividing with square roots, we can combine the two roots into one and then simplify.
#sqrt80/sqrt5 = sqrt(80/5)#

#sqrt(80/5) = sqrt16 = 4#

Second method Write 80 as a product of factors,
Note that #80 = 16 xx 5#

#sqrt80/sqrt5 = sqrt(16xx5)/sqrt5" separate into two roots"#

#(sqrt16 xx sqrt5)/sqrt5 " " = sqrt16 = 4#

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