How do you convert $(2, - 3)$ $(2, -3)$ to polar form?

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Answer 1 · 2016-05-31T01:30:56

Polar Form: (3.6,-56.3)

Polar format: $(r, θ)$ $(r, theta)$

$r = \sqrt{x^{2} + y^{2}}$ $r=sqrt(x^2+y^2$

$θ = {tan}^{- 1} (\frac{y}{x})$ $theta=tan^-1(y/x)$

Apply both formulas when going from Cartesian -> Polar

$\sqrt{2^{2} + {(- 3)}^{2}} = \sqrt{13} = 3.6$ $sqrt(2^2+(-3)^2) = sqrt(13) = 3.6$

$θ = {tan}^{- 1} (\frac{- 3}{2}) \approx - 0.98 radians$ $theta = tan^-1 ((-3)/2) ~~ -"0.98 radians"$

Thus our answer of:

Polar format of $(2, - 3)$ $(2,-3)$ Cartesian:

$(3.6, 0.98)$ $(3.6, 0.98)$

How do you convert (2, -3)(2,−3) (2, -3) to polar form?