What volume of 1.25 M #CaF_2# solution is needed to provide 4.00 mol #CaF_2#?

Question

1742 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-29T19:36:55

3.2 L of 1.25M CaF2

For this problem, you will need to know the formula for molarity.

#Molarity = (mol) / (volume(L))#

or

#M= n/V#

Given:

M = 1.25
n = 4.00 mol

Plug in your given data:

#1.25 = (4.00 mol)/V#

#V# = 3.2 L