How do you simplify # (4 sqrt12) * (3 sqrt20)#?

Question

1632 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-27T14:57:29

#= 48 sqrt ( 15) #

#(4 sqrt 12 ) * ( 3 sqrt 20)#

# = 4 * sqrt 12 * 3 * sqrt 20 #

Note: Prime factorisation is expressing a number as a product of its prime factors.

# 4 * sqrt 12 * 3 * sqrt 20 = 4 * color(green)(2 sqrt3) * 3 * color(blue)(2 sqrt5 #

#4 * color(blue)(2) * sqrt3 * 3 * color(blue)(2 ) * sqrt5 = 4 * 3 * color(blue)( 2 * 2) * sqrt3 * sqrt5 #

#= 48 sqrt3 * sqrt5 #

#= 48 sqrt ( 3 * 5) #

#= 48 sqrt ( 15) #