What is the derivative of $y =x^2-5x+10$ ?

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Answer 1 · 2016-05-26T03:01:37

$d/dx (x^2−5x+10)=2x-5$

The power rule gives the derivative of an expression of the form $x^n$ .

$d/dx x^n=n*x^{n-1}$

We will also need the linearity of the derivative

$d/dx (a*f(x)+b*g(x))=a*d/dx(f(x))+b*d/dx (g(x))$

and that the derivative of a constant is zero.

We have

$f(x)=x^2−5x+10$

$d/dxf(x)=d/dx (x^2−5x+10)=d/dx (x^2)−5d/dx(x)+d/dx(10)$

$=2*x^1-5*1*x^0+0=2x-5$

What is the derivative of y =x^2-5x+10y =x^2-5x+10?