How do you solve $- 3 (4 + x) = 15$ $-3(4 + x) = 15$ ?

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How do you solve $- 3 (4 + x) = 15$ $-3(4 + x) = 15$ ?

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Answer 1 · 2016-05-12T09:34:33

x=-9

Explanation:

$- 3 (4 + x) = 15$ $-3(4+x)=15$

Multiply every 4 and x by -3
$- 12 - 3 x = 15$ $-12-3x=15$

Carry over -12 to the right side of the equal sign and add it to 15 and cancel out -12 on the other side:
$- 3 x = 15 + 12$ $-3x=15+12$
$- 3 x = 27$ $-3x=27$

Divide 27 by -3 and cancel out -3 on the other side:
$- 3 \frac{x}{- 3} = \frac{27}{- 3}$ $-3x/-3=27/-3$

The answer is x=-9

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How do you solve $- 3 (4 + x) = 15$ $-3(4 + x) = 15$ ?

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Explanation:

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How do you solve $- 3 (4 + x) = 15$ $-3(4 + x) = 15$ ?