How do you simplify ${(\frac{b^{10}}{b^{3}})}^{- 2}$ $(b^10/b^3)^-2$ ?

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How do you simplify ${(\frac{b^{10}}{b^{3}})}^{- 2}$ $(b^10/b^3)^-2$ ?

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Answer 1 · 2016-05-07T07:57:19

Apply the laws of Indices. See working below.

Explanation:

${(\frac{b^{10}}{b^{3}})}^{- 2}$ $(b^10/b^3)^-2$ = $(\frac{b^{- 20}}{b^{- 6}})$ $(b^-20/b^-6)$ = $(b^{- 20}) (b^{6})$ $(b^-20)(b^6)$ = $b^{- 14}$ $b^(-14)$

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How do you simplify ${(\frac{b^{10}}{b^{3}})}^{- 2}$ $(b^10/b^3)^-2$ ?

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How do you simplify ${(\frac{b^{10}}{b^{3}})}^{- 2}$ $(b^10/b^3)^-2$ ?