How do you solve $12 x - 20 = x^{2}$ $12x-20=x^2$ using the quadratic formula?

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Answer 1 · 2016-04-24T17:46:17

$x = 2, 10$ $x=2,10$

Let us re-write the equation in the standard form $x^{2} - 12 x + 20 = 0$ $x^2-12x+20=0$

Here, we are given a quadratic equation.
The standard form of a quadratic equation is $a x^{2} + b x + c = 0$ $ax^2 + bx + c = 0$

This means the equation has 2 roots.

The quadratic formula to find the roots of the equation is

$x_{1, 2} = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x_(1,2)=(-b +-sqrt(b^2-4ac))/(2a)$

The step-by-step walk through to solving the equation is shown below.

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How do you solve 12x−20=x212x-20=x^2 using the quadratic formula?