How do you solve $x = y + 3$ $x= y + 3$ and $3 x - 2 y = 4$ $3x - 2y = 4$ using substitution?

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Answer 1 · 2016-04-21T08:15:01

$y = - 5$ $y=-5$

$x = - 2$ $x=-2$

$x = y + 3$ $x=y+3$ ----1
$3 x - 2 y = 4$ $3x-2y=4$ ----2

subtitute 1 into equation 2

$3 (y + 3) - 2 y = 4$ $3(y+3)-2y=4$
$3 y + 9 - 2 y = 4$ $3y+9-2y=4$
$y + 9 = 4$ $y+9=4$
$y = - 5$ $y=-5$

subtitute $y = - 5$ $y=-5$ into equation 1

$x = (- 5) + 3$ $x=(-5)+3$
$x = - 2$ $x=-2$

How do you solve x=y+3x= y + 3 and 3x−2y=43x - 2y = 4 using substitution?