How do you find the derivative of #(x^2-2)/x#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Diana S. Apr 1, 2016 by using u/v formula Explanation: #d/dx((x^2-2)/x)# = #(x(2x-0)-(x^2-2)(1))/x^2# = #(2x^2-x^2+2)/x^2# = #(x^2+2)/x^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1294 views around the world You can reuse this answer Creative Commons License