What is the vertex of the parabola $y = {(x + 16)}^{2} + 7$ $y=(x+16)^2+7$ ?

Question

What is the vertex of the parabola $y = {(x + 16)}^{2} + 7$ $y=(x+16)^2+7$ ?

1 Answer

Impact of this question

1513 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-29T14:56:04

$(- 16, 7)$ $(-16,7)$

Explanation:

The vertex form of a parabola is: $y = a {(x - h)}^{2} + k$ $y=a(x-h)^2+k$
The vertex can be expressed by $(h, k)$ $(h,k)$

In the given equation: $y = {(x + 16)}^{2} + 7$ $y=(x+16)^2+7$
$h$ $h$ is equal to $- 16$ $-16$
k is equal to $7$ $7$
$(h, k)$ $(h,k)$
$(- 16, 7)$ $(-16,7)$

Science

Math

Humanities

... and beyond

What is the vertex of the parabola $y = {(x + 16)}^{2} + 7$ $y=(x+16)^2+7$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the vertex of the parabola y=(x+16)2+7y=(x+16)^2+7?

1 Answer

Explanation:

Related questions

Impact of this question

What is the vertex of the parabola $y = {(x + 16)}^{2} + 7$ $y=(x+16)^2+7$ ?