What is the slope of the line perpendicular to $y = \frac{3}{8} - 6$ $y=3/8-6$ ?

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Answer 1 · 2016-03-20T00:16:13

slope= $- \frac{8}{3}$ $-8/3$

I'm assuming you meant $y = \frac{3}{8} x - 6$ $y=3/8x-6$ .
$\frac{3}{8}$ $3/8$ is the slope of the line.

To find the slope of the line perpendicular to this line, you need to take the negative reciprocal of the slope.

In this case, the negative reciprocal of $\frac{3}{8}$ $3/8$ is $- \frac{8}{3}$ $-8/3$ .

Therefore, the slope of the line perpendicular to this line would be $- \frac{8}{3}$ $-8/3$ .

What is the slope of the line perpendicular to y=3/8-6 y=38−6 y=3/8-6 ?