How do you solve $35=w(w-2)$ ?

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Answer 1 · 2016-03-19T14:24:32

The solution is $w = 7$ and $w = -5$

Firstly change $35 = w(w - 2)$ into a standard form
So by factorizing

Expand the bracket

$35 = w^2 - 2w$

then put all terms on the left Hand side (LHS) and equate to zero,
So

$w^2 -2w -35 = 0$

Now factor the quadratic by looking for a pair of factors of $-35$ whose sum is $-2$ , which are $-7$ and $5$ :

$(w -7)(w + 5) =0$

For this to be true $w-7=0$ or $w+5=0$ , so $w=7$ or $w=-5$ .

How do you solve 35=w(w-2) 35=w(w-2) ?