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How do you differentiate # f(x) =cos(3x -2) #?

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1 Answer

Mar 7, 2016

#(df)/dx = -3sin(3x-2)#

Explanation:

Use substitution.

If you have a function like this, let,say, #t =3x -2#
Then #f(t) = cost# and #(df)/dt = -sint#
#(dt)/dx = 3#
#(df)/dx = (df)/dt*(dt)/dx = -sint*3#

#(df)/dx = -3sin(3x-2)#

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