How do you solve $\frac{1}{5} x - 4 = 3 - \frac{1}{2} x$ $1/5x - 4 = 3 -1/2x$ ?

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How do you solve $\frac{1}{5} x - 4 = 3 - \frac{1}{2} x$ $1/5x - 4 = 3 -1/2x$ ?

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Answer 1 · 2016-03-06T11:05:22

x=10

Explanation:

$\frac{1}{5} \cdot x + \frac{1}{2} \cdot x = 7$ $1/5*x+1/2*x=7$
now take x common $(\frac{1}{5} + \frac{1}{2}) \cdot x$ $(1/5+1/2)*x$
now $\frac{1}{5} + \frac{1}{2} = \frac{7}{10}$ $1/5+1/2=7/10$
seven will cancel out from both the sides. therefore $\frac{1}{10} \cdot x = 1$ $1/10*x=1$
so x comes out to be 10

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How do you solve $\frac{1}{5} x - 4 = 3 - \frac{1}{2} x$ $1/5x - 4 = 3 -1/2x$ ?

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